psholtz
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Just so I have the concept of a singular solution down correctly, suppose I have an equation like:
\left(x+y\right)^2y' = 0
This admits of two solutions:
y=-x
and, from:
y' = 0
y = C
where C is a constant.
So the "two" solutions for the equation would be:
y_1=-x, y_2 = C
In this case, y=-x would be considered the "singular" solution, correct?
\left(x+y\right)^2y' = 0
This admits of two solutions:
y=-x
and, from:
y' = 0
y = C
where C is a constant.
So the "two" solutions for the equation would be:
y_1=-x, y_2 = C
In this case, y=-x would be considered the "singular" solution, correct?