Do Sinusoidal Equations Represent Different Wave Types?

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The discussion confirms that the equation y = a sin(wt) represents a wave pulse, while y = a sin(wt – kx) describes a progressive wave. It emphasizes that a wave exists across all x and t, whereas a wave pulse is localized in time and space. The participants also conclude that the two given wave equations, y1 = a cos(kx – wt) and y2 = a sin(kx + wt), do not produce stationary waves, encouraging users to verify this by adding the equations themselves for clarity.

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Amith2006
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Sir,
1)Is it true that y = a sin(wt) is the equation of a wave pulse and y = a sin(wt – kx) is the equation of a progressive wave?
I think it is true.
2)Will the following 2 waves produce stationary waves?
y1 = a cos(kx – wt)
y2 = a sin(kx + wt)
I think the answer is No. What do you say Sir?
 
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Amith2006 said:
Sir,
1)Is it true that y = a sin(wt) is the equation of a wave pulse and y = a sin(wt – kx) is the equation of a progressive wave?

y(0,t)=a\sin(\omega t) is the wave as seen from x=0. If you were to measure the vertical displacement y(0,t) then you would find it to vary simple harmonically.

A wave exists for all x and t whereas a pulse is a portion of a wave which exists for some time, much like the wave pulse generated when you shake one end of a string (the other end being fixed) before it strikes the end and standing waves are set up. To describe a pulse, you need to describe the wavefunction as y(x,t) for some region when it is "on" and zero elsewhere. So you need to include the span of the wave pulse.

2)Will the following 2 waves produce stationary waves?
y1 = a cos(kx – wt)
y2 = a sin(kx + wt)
I think the answer is No. What do you say Sir?

Why don't you add the waves and see for yourself?? Its not that difficult and the best way to figure out is to add them yourself rather than have someone tell you the answer. :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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