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atyy said:http://arxiv.org/abs/1206.6538 has interesting comments about GW from binaries.
Great find! This did not exist when I last looked (2011). It will take much time to digest...
The discussion centers on whether a free-falling charge radiates electromagnetic and gravitational waves. It is established that while an electron is a point-like object, it is surrounded by an extended Coulomb field that contains stress-energy, which can radiate. The conversation highlights that a charge does not follow a geodesic due to its extended nature, leading to radiation when subjected to varying gravitational fields. Key conclusions include that radiation is independent of the observer and occurs when a charge does not move along a geodesic.
PREREQUISITESPhysicists, researchers in theoretical physics, and students studying electromagnetism and general relativity who seek to understand the nuances of radiation from charged particles in gravitational fields.
atyy said:http://arxiv.org/abs/1206.6538 has interesting comments about GW from binaries.
TrickyDicky said:we don't have such a metric for a spacetime compatible with GWs.
TrickyDicky said:Yes, but that motion has to be disturbed to register a GW.
I thought the thread's discussion (though switching back and forth from EM source to gravitational source here and there) was more centered in the sources.PeterDonis said:Perhaps not for sources, but we do for detectors like LIGO and LISA. By the time a GW reaches such a detector, it's weak enough to be treated by linearized GR. MTW has at least one whole chapter on this IIRC (my copy isn't handy right now to check).
PeterDonis said:You're missing the point: the geodesic motion *is* the "disturbance". Saying that the mirrors follow geodesics that have bumps and wiggles in them, and saying that the mirrors are disturbed by the GW, are different ways of saying the same thing. There is no "disturbance" over and above the behavior of the geodesics due to the time-dependence of the metric.
TrickyDicky said:"The concept of geodesics becomes critical in general relativity, since geodesic motion may be thought of as "pure motion" (inertial motion) in spacetime, that is, free from any external influences."
I consider GWs an external influence, don't you?
TrickyDicky said:the detector is ultimately a very specialized , very sensitive type of accelerometer.
TrickyDicky said:I mean you don't bring up the time-dependence of the metric when talking about the absolute acceleration notion in GR.
It isn't exactly a regular accelerometer as I said, in fact rather than proper acceleration what GW detectors measure are variations ("fluctuations") in proper acceleration, much like gravity gradiometers do.PeterDonis said:No, it isn't. It doesn't measure proper acceleration; it measures fluctuations in spacetime curvature, which manifest as fluctuations in the proper distance between two endpoints that are moving on geodesics.
See above.PeterDonis said:Because proper acceleration is curvature of the *path*, not spacetime; it is a different thing from curvature of spacetime, time-varying or otherwise. Here we're talking about curvature of spacetime; the paths of the mirrors in the GW detector are straight, but they're straight in a manifold that's curved, and whose curvature varies with time.
Hi WN, I made clear that difference when I spoke of the gravity gradiometer that in fact involves several accelerometers for neighbouring worldlines.WannabeNewton said:The GW detection involves the geodesic deviation equation of neighboring geodesics and is therefore related directly to the space - time curvature (the time dependent perturbations when we are talking about GW waves) as can be seen in the equation. Proper acceleration (as measured by an accelerometer) is related to a single wordline. This is exactly what PeterDonis has said already.
Sorry I typed up my response and left it alone for a bit before submitting so I didn't get to see your response before then.TrickyDicky said:Hi WN, I made clear that difference when I spoke of the gravity gradiometer that in fact involves several accelerometers for neighbouring worldlines.
This may be just nit-picking but I always thought geodesic deviation to be caused by tidal forces is there a straight forward way to relate GWs and tidal forces?WannabeNewton said:The GW detection involves the geodesic deviation equation of neighboring geodesics and is therefore related directly to the space - time curvature (the time dependent perturbations when we are talking about GW waves) as can be seen in the equation.
http://arxiv.org/pdf/gr-qc/9712019.pdfTrickyDicky said:This may be just nit-picking but I always thought geodesic deviation to be caused by tidal forces is there a straight forward way to relate GWs and tidal forces?
WannabeNewton said:http://arxiv.org/pdf/gr-qc/9712019.pdf
Go to, in particular, page 159 out of 238 in the pdf itself (not page 159 in the notes).
Yeah that would be cool. It is quite instructive to take a ring of test particles as your family of closely separated geodesics and see how the gravitational waves expand and shear them. There is a close relationship between the Weyl tensor as a contributor to shear and the Ricci tensor as a contributor to expansion, as codified by the Raychaudhuri equation (however they are coupled so it isn't exactly totally independent)TrickyDicky said:I think I'll start a new thread on GW detection, tidal forces and accelerometers in order not to go so much OT here.