Does a Function Exist Given Specific Function Values and Derivative Constraints?

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Homework Help Overview

The problem involves determining the existence of a function f given specific values and constraints on its derivative. The values provided are f(0) = -1, f(2) = 4, and the condition f'(x) ≤ 2 for all x.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of the mean value theorem for the function on the interval [0,2], particularly focusing on the calculation of the average rate of change and its relationship to the derivative constraint.

Discussion Status

The discussion is exploring the implications of the mean value theorem and how it relates to the given constraints. Some participants are questioning whether the derived average rate of change aligns with the derivative condition, leading to differing interpretations of the function's existence.

Contextual Notes

There is a focus on the conditions imposed by the mean value theorem and the specific values of the function at given points, which may influence the conclusions drawn about the function's existence.

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Homework Statement


Does the function f exist when f(0)=-1, f(2)=4, and f'(x)≤2 for all values of x? Justify your answer.

The Attempt at a Solution


I am having some trouble with where to start...and end. Thanks for your help.
 
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What would the mean value theorem tell you about f(x) on the interval [0,2]?
 
What would the mean value theorem tell you about f(x) on the interval [0,2]?
It tells me that there exists a number c in (0,2) such that f'(c) = (f(2)-f(0))/(2-0)
 
Ok. What is (f(2)-f(0))/(2-0) as a number?
 
so 2.5 is not less than or equal to 2, so the function would not exist?
 
Loppyfoot said:
so 2.5 is not less than or equal to 2, so the function would not exist?

Exactly.
 
Great. Thank you, Sir.
 

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