Does a single electron produce a measurable current?

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Single electron counters appear to exist, the Jap. have one that even determines direction, and they discuss atto-amperage. What I don't quite get is, if a single electron flows, is there an observed very small current ? Since an electron is the smallest size, more sensitive equipment then can never discover an even smaller current, right ?

I accept the notion that models may call for a smallest indivisible unit, I'm only wondering how we establish that we have indeed located that size. Thanks for commenting..
 
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If the particle undergoes a finite and quasiperiodic motion, then the electric current could be quantified as the charge of the particle divided by the period. For example, for the hydrogen atom:

[tex] \left\{\begin{array}{lcl}<br /> \frac{m_{e} v^{2}}{r} & = & \frac{k_{0} e^{2}}{r^{2}} \\<br /> <br /> m_{e} v r & = & \hbar<br /> \end{array}\right. \Rightarrow <br /> \left\{\begin{array}{lcl}<br /> v^{2} r & = & \frac{k_{0} e^{2}}{m_{e}} \\<br /> <br /> v r & = & \frac{\hbar}{m_{e}}<br /> \end{array}\right.[/tex]

[tex] \left\{\begin{array}{lcl}<br /> v & = & \frac{k_{0} e^{2}}{\hbar} \\<br /> <br /> r & = & \frac{\hbar^{2}}{m_{e} k_{0} e^{2}}<br /> \end{array}\right.[/tex]

The period is:

[tex] T = \frac{2 \pi r}{v} = \frac{1}{4 \pi^{2} c} \frac{(h c)^{3}}{m_{e} c^{2} (k_{0} e^{2})^2} = 1.520 \times 10^{-16} \, \mathrm{s}[/tex]

This gives a current of:

[tex] I = \frac{e}{T} = 1.05 \, \mathrm{mA}[/tex]
 
thx for formula, could you also paste the terms, definitions ? Also the last term is not clear to me,i.e. the 1.05 mA (!). I'm not in physics, would appreciate discussion of hardware level, if any. I read the wikipedia articles, they did not really center on measurement and instrument sensitivity.
 
No, I can't. Look for Bohr model lectures. [itex]mA[/itex] stands for 'milliampere'. Learn the prefixes for SI units.
 
ndvcx said:
What I don't quite get is, if a single electron flows, is there an observed very small current ?

Current density can be seen as the product of the number of charges and their drift speed:
http://en.wikipedia.org/wiki/Current_density

So according to the first equation in that link, nothing prevents having a single electron going at arbitrary low speed, from which you can easily get an atto-ampere if you want. Current depends on both the number of charges and their drift velocity (itself a function of resistance and voltage in paticular).