_joey said:
\Sigma_{k=0}^{\infty}\frac{a^k}{(k-x)!}
Thanks!
If x is positive, then you have factorials of a negative number, which is a tad unusual.
If x is not an integer, then you have factorials of a non-integer. Also unusual.
If x is a negative integer, you have
<br />
\begin{align*}<br />
\Sigma_{k=0}^{\infty}\frac{a^k}{(k-x)!} & = a^x \Sigma_{k=0}^{\infty}\frac{a^{k-x}}{(k-x)!} \\<br />
& = a^x \Sigma_{k=-x}^{\infty} \frac{a^k}{k!} \\<br />
& = a^x \left( e^a - \Sigma_{k = 0}^{-x-1} \frac{a^k}{k!} \right)<br />
\end{align*}
This is the exponential function, scaled and translated.
P.S. Added in edit. Bad description there sorry. It is not scaled and translated by a constant. You subtract a polynomial, and then divide by a
-x.
Cheers -- sylas
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