Does Bouncing Increase the Impact Force Required in Collisions?

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SUMMARY

The discussion centers on the physics of collisions, specifically examining the impact force required for an egg drop apparatus that bounces upon hitting the ground. The force calculated for a non-bouncing scenario is 3.09 Newtons, with the apparatus mass being 0.078 kg and a final velocity of 9.89 m/s. It is established that a bouncing collision typically requires a larger force than a non-bouncing one due to the additional energy needed to reverse the object's momentum. The concepts of elastic and inelastic collisions, along with the momentum-impulse theorem, are crucial to understanding these dynamics.

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Judah
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-An Egg Drop began at rest and fell through approximately 5-m. Assume that its momentum was changed in a time of 0.25-s. If your apparatus bounced when hitting the ground, would this require a smaller force than in #4, a larger force than in #4, or the same force as in #4? Explain….

-Note: My class is still on collisions: elastic, inelastic, and momentum/impulse therom

-The force from number 4 is 3.09 Newtons.
Mass of the apparatus is .078 kg.
Velocity final is 9.89 m/s.

What force is required for an object to bounce?

Does the force have to be larger than its weight?
 
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Can you show us your attempt for the problem ?
 
Do you know what force is?
 

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