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Momentum and Impulse: Dropping an Object

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  1. Jan 22, 2012 #1
    1. A 2 kilogram egg drop apparatus began at rest and fell through approximately 5-m. Assume that it’s momentum was changed to zero in a time of 0.25-s.
    --What force stopped your apparatus?
    ---Mass=2kg
    ---Distance=-5m
    ---Time=.25-s

    2.-Force(Time)=Mass(Velocity)

    3.Velocity final for the apparatus would be the square root of 2(-9.8)(-5). About 9.99m/s.
    Do i just plug in that for the equation above?
     
  2. jcsd
  3. Jan 23, 2012 #2

    ehild

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    Equation 2 should be written as Force * time = Mass *(change of velocity)
    Yes, you nee only plug in the data to get the average force of impact.

    ehild
     
  4. Feb 1, 2012 #3
    Thanks I got the answer for that. Can you answer another question?
    If the object were to bounce would it require a larger, smaller, or the same force?
     
  5. Feb 2, 2012 #4

    ehild

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    What is the change of the velocity if the object bounces?

    ehild
     
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