Momentum and Impulse: Dropping an Object

[Judah]

1. A 2 kilogram egg drop apparatus began at rest and fell through approximately 5-m. Assume that it’s momentum was changed to zero in a time of 0.25-s.
--What force stopped your apparatus?
---Mass=2kg
---Distance=-5m
---Time=.25-s

2.-Force(Time)=Mass(Velocity)

3.Velocity final for the apparatus would be the square root of 2(-9.8)(-5). About 9.99m/s.
Do i just plug in that for the equation above?

 

[ehild]

2.-Force(Time)=Mass(Velocity)

3.Velocity final for the apparatus would be the square root of 2(-9.8)(-5). About 9.99m/s.
Do i just plug in that for the equation above?

Equation 2 should be written as Force * time = Mass *(change of velocity)
Yes, you nee only plug in the data to get the average force of impact.

ehild

 

[Judah]

Thanks I got the answer for that. Can you answer another question?
If the object were to bounce would it require a larger, smaller, or the same force?

 

[ehild]

What is the change of the velocity if the object bounces?

ehild