Does Bringing a Metal Ball Near a Charged Dielectric Transfer Energy?

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SUMMARY

The discussion centers on the interaction between a charged cylindrical dielectric and an uncharged metal ball. When the metal ball is brought near the positive end of the dielectric charged at 100KV, it experiences electrostatic induction, leading to charge separation without acquiring a net charge. The energy from the electrostatic field is utilized to separate the charges within the metal ball, indicating that energy transfer occurs. The dielectric itself does not change in charge but influences the distribution of charges in the metal ball.

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Imagine you have a cylindrical dielectric charged with 100KV on one end and -100KV on the other end.

Now take an uncharged metal ball and bring it close to the positive end of the dielectric.

From what I understand, the metal ball will be induced into having a charge that will come close to -100KV, depending on how close it comes to the dielectric, via Electrostatic Induction.

When this is done, is there any transfer of energy? Does the dielectric change in any way? If so, in what way?
I can't find any equations that characterized the change in charged matter, or the change in uncharged matter..
 
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From what I understand, the metal ball will be induced into having a charge that will come close to -100KV
Charge is not induction. The metal ball will not get a net charge (unless it has contact to something else) - it will have some charge separation, with less electrons close to the -100kV-point and more electrons far away.

Why do you use a cylindrical dielectric? Two charged objects (conductivity does not matter) would do the same.

When this is done, is there any transfer of energy?
Some energy of the electrostatic field is used to separate the charges.
 

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