Does centrifugal force affect weight at different latitudes on Earth?

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Centrifugal force, resulting from Earth's rotation, slightly reduces the effect of gravity, which varies by latitude. At the equator, the effective gravity is lower due to higher centrifugal force, while at the poles, gravity is stronger because of both reduced centrifugal force and proximity to Earth's center. An object weighing 160 lbs at the equator would weigh approximately 0.5% more at the North Pole. NASA's satellites have mapped these gravitational variations, revealing differences caused by geographical features but not specifically measuring centrifugal effects. This discussion highlights the interplay between gravity and centrifugal force across different latitudes on Earth.
John E4-D5
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As a result of various searches on the Net, I have ended up here on this fantastic site. Specifically, it was an old 2008 thread in which was closed, so in order for me to expand on such discussion I've decided to make my own thread; by which I will go a slightly different direction with.

Gravity pulls everything towards the center of the earth, and centrifugal force slightly lessens the effect of gravity's pull. Due to Earth's spin, of course.

Now, at the equator the Earth spins 1500 - 1700 mph. I'm not sure what the specific speed is because everyone uses a different number. But that is besides the point.

Here's my thought experiment for you: If I fly to the equator, and weigh myself at 160 lbs, and then I go to the North Pole, will I weigh more or less than 160 lbs.? If so, by how much?

The circumference of the Earth at the equator is much more than the circumference of the Earth close to the North pole, which would mean that the effects of the centrifugal force would be less, therefore I should weigh more right?

Would this be a reasonable experiment to do, or has it already been done?

Very much looking forward to your replies and insights! Thank you!
 
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John E4-D5 said:
As a result of various searches on the Net, I have ended up here on this fantastic site.
Welcome to PF!
Gravity pulls everything towards the center of the earth, and centrifugal force slightly lessens the effect of gravity's pull. Due to Earth's spin, of course.
Yes.
Now, at the equator the Earth spins 1500 - 1700 mph. I'm not sure what the specific speed is because everyone uses a different number.
Can't you do the calculation yourself? Those values actually aren't all that close.
Here's my thought experiment for you: If I fly to the equator, and weigh myself at 160 lbs, and then I go to the North Pole, will I weigh more or less than 160 lbs.? If so, by how much?

Would this be a reasonable experiment to do, or has it already been done?
NASA has satellites that map the Earth's gravitational field in exquisite detail, being able to detect the differences caused by mountain ranges, oceans and the varying thickness of the crust. Here's the amount of variation:
Effective gravity on the Earth's surface varies by around 0.7%, from 9.7639 m/s2 on the Nevado Huascarán mountain in Peru to 9.8337 m/s2 at the surface of the Arctic Ocean.[4] In large cities, it ranges from 9.766 in Kuala Lumpur, Mexico City, and Singapore to 9.825 in Oslo and Helsinki...

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level effective gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh about 0.5% more at the poles than at the Equator.
https://en.wikipedia.org/wiki/Gravity_of_Earth#Variation_in_gravity_and_apparent_gravity

Note that in addition to the centrifugal force, there is also the issue that when on the pole, you are closer to the Earth's center.
 
russ_watters said:
NASA has satellites that map the Earth's gravitational field in exquisite detail, being able to detect the differences caused by mountain ranges, oceans and the varying thickness of the crust.
It should be noted, that those satellites do not detect the differences due to centrifugal effects.
 
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For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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