Does cos(1/z) Verify Picard's Big Theorem Near z=0?

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Homework Help Overview

The discussion revolves around verifying Picard's Theorem for the function cos(1/z) at the point z = 0, particularly focusing on the implications of essential singularities in complex analysis.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • The original poster attempts to understand a solution involving the transformation of z and its implications for the values of cos(1/z) near z = 0. Some participants question the assumptions about the range of the cosine function when its argument is complex, while others suggest exploring related concepts like the Casorati-Weierstrass theorem.

Discussion Status

Participants are exploring the nuances of Picard's Theorem and its application to the function in question. There is a recognition of the need for clarification on the definitions of Picard's Theorem, and some guidance has been offered regarding relevant examples and concepts.

Contextual Notes

There is a mention of potential confusion regarding the nature of the cosine function when extended to complex arguments, as well as the distinction between the little and big versions of Picard's Theorem. The original poster expresses uncertainty about the reasoning behind the conclusions drawn in the provided solution.

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Homework Statement


Verify Picard's Theorem for cos(1/z) at z = 0

Homework Equations


The theorem:
A function with an essential singularity assumes every complex number, with possibly one exception, as a value in any neighborhood of this singularity

The Attempt at a Solution


I have a solution that I don't understand (from a manual). What the manual does is break out z to get
[tex]z = \frac{1}{log(c\pm \sqrt{c^2-1}}[/tex] for an arbitrary complex constant c. Getting there is trivial enough but I don't get the conclusion.

Values of the logarithm can be chosen to make [tex]|z| < \epsilon[/tex] for any positive [tex]\epsilon[/tex], so that cos(1/z) achieves the value c in any neighborhood of z = 0.

I understand that you can make z arbitrarily small by choosing a k high enough in the logarithm, but intuitively I'd think cos(z) wouldn't leave [-1, 1] no matter how fast it jumped between them. Intuition be damned, I can't see the reasoning at all. Because I can get a very large input in the cosine function I know the function can output any complex number? How?

Guessing it's something rather silly I'm missing here but there you go.
Any help would be appreciated, cheers.
 
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I think you're missing the fact that [itex]\cos{w}[/itex] does not necessarily sit in the interval [itex][-1,1][/itex] when [itex]w[/itex] is complex. For example, if [itex]w[/itex] is pure imaginary, then [itex]\cos{w} = \cosh{|w|}[/itex].

So the point is that you can use the unboundedness from a large imaginary part of [itex]w =1/z[/itex] plus the phase degree of freedom from the real part of [itex]w[/itex] to get more or less any complex number you want.
 
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You're right, that completely flew me by. Thanks, wasn't that tricky after all.
 
usn7564 said:
How?

First, better define what you mean by Picard's Theorem. He has two, the little one and the big one.

Little: Every entire function that's not a polynomial has an essential singularity at infinity.

Big: A function with an essential singularity achieves every value, with at most one exception, infinitely often in any neighborhood of the singularity.

I think you want the big one.

Any help would be appreciated, cheers.

First do a Wikipedia on Casorati-Weierstrass, study the example for [itex]e^{1/z}[/itex], then apply that example to your problem.
 

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