Does cylinder diameter affect force measurement on a hydraulic press?

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SUMMARY

The discussion centers on the relationship between cylinder diameter and force measurement in a hydraulic press setup. A 50-ton hydraulic press with a 4-inch diameter cylinder head is used to measure push-in and pull-out forces via a load cell. It is established that while the force transmitted through the load cell remains constant, the stress on the load cell increases if its area is smaller than that of the cylinder head. This indicates that the load cell can accurately measure the force applied to the bushing, despite the differences in diameters.

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This discussion is beneficial for mechanical engineers, hydraulic system designers, and technicians involved in force measurement and calibration of hydraulic presses.

resjsu
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Hello All,
At work we will begin press fitting bushings into iron components.
The customer has specified a range for the "push-in" and "pull-out" force so we bought a load cell to measure the values.

My question is, when we approximate force on our standard 50-ton press with a 4inch diameter cylinder head, we multiply the psi by the area of the cylinder head and arrive at a force. So, if the surface area were smaller than the resulting force would be less correct?

Now then referring to the attached drawing, since our arbor is smaller in diameter than our cylinder head and load cell, is the force that is actually being applied to the bushing less than the force being applied to the load cell?

With this setup will the load cell accurately measure the force the bushing is experiencing?

What is wrong with my understanding of pressure/force and how the diameters affect each measurement?

Thank you for your help and time!
 

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This is a hydraulic press, right? You speak of multiplying psi (pressure) by cylinder area to calculate force, so this sounds hydraulic.

That force, when tranmitted through the load cell remains the same. If the area of the load cell is less than the cylinder area, the stress on the load cell will be higher because the same force must pass through a reduced area.
 

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