Does {Sn} Converge to L if and only if {Sn - L} Converges to 0?

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SUMMARY

The discussion centers on the convergence of a sequence {Sn} to a limit L, establishing that {Sn} converges to L if and only if the sequence {Sn - L} converges to 0. The key argument presented involves the application of the epsilon-delta definition of limits, demonstrating that |Sn - L| < ε is equivalent to |(Sn - L) - 0| < ε. The user confirms their understanding by deriving that the limit of {Sn - L} equals 0, thus validating the convergence condition.

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Homework Statement


Show that a sequence Sn will converge to a limit L if and only if Sn - L converges to 0

Homework Equations



{Sn} converges to L if and only if {Sn - L } converges to 0

The Attempt at a Solution



Is it enough to just say

{Sn} converges to L if and only if |Sn - L| < \epsilon if and only if |(Sn - L) - 0| < \epsilon if and only if {Sn - L}$ converges to 0

I'm learning this off a random pdf so I don't have the answers.

Is this enough? Any suggestions would be appreciated. Also is there a way to turn on Latex?
 
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since Sn converges to L, then :
lim Sn = L ... (1)
for the sequence {Sn-L}
lim ( Sn - L ) = lim Sn - lim L = L - L = 0
so {Sn-L} converges to 0

its looks easy for me, or i missed something :S
 

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