Does the Chain Rule Apply to Derivatives of Inner Products?

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SUMMARY

The discussion confirms that the chain rule applies to the derivatives of inner products in the context of L² spaces. Specifically, it establishes that for inner products defined as = Integral(f#g, w.r.t. x,-Pi,+Pi), the derivative with respect to y satisfies D_y() = + . This holds true for bilinear forms, as long as the functions involved are linear in both variables. The proof relies on the properties of bilinear combinations.

PREREQUISITES
  • Understanding of inner products in L² spaces
  • Knowledge of partial derivatives and their applications
  • Familiarity with bilinear forms and their properties
  • Basic integration techniques over defined intervals
NEXT STEPS
  • Study the properties of bilinear forms in functional analysis
  • Learn about the application of the chain rule in multivariable calculus
  • Explore advanced topics in L² space, including convergence and continuity
  • Investigate the implications of inner product derivatives in quantum mechanics
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Mathematicians, physicists, and students studying functional analysis or multivariable calculus, particularly those interested in the applications of inner products and derivatives in theoretical contexts.

brydustin
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I am trying to take the derivative of an
inner product (in the most general sense
over L^2), and was curious if the
derivative follows the "chain rule" for
inner products.

i.e. Does D_y(<f,g>) = <D_y(f),g> + <f,D_y(g)>
where D_y is the partial derivative w.r.t. y.

So for example, IT IS TRUE that if f=x*y and g=sin(x*y)
and the inner product <f,g> = Integral(f#g, w.r.t. x,-Pi,+Pi), f# = complex conj. of f.
then the equality holds.
In other words, differentiating w.r.t. y and integrating w.r.t x the formula holds.
It seems more trivial if the variable which is being differentiated & integrated is the same.
But is it true in general?
What if we are differentiating more abstract inner products (i.e. not necessarily integration).
 
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