Does the placement of weight affect tension in 3D?

AI Thread Summary
The placement of weight in a 3D rectangular box affects the tension in the strings connected to it. When weight is placed at the center, the tension remains balanced, as the weight vector acts uniformly downward. However, positioning the weight at a corner creates an off-center center of mass, resulting in torque that alters the tension in the strings. This torque necessitates additional tension on one or two strings to counterbalance the imbalance created by the off-center weight. Understanding these dynamics is crucial for accurate modeling in physics and engineering contexts.
Icah
If you have a rectangular box connected on 3 sides with strings, and you hold all the strings together at a point, with your hand; then you put a weight in the center of the box, which is open, would the tension on the strings differ than if you put the weight at a corner. Please describe it to me in detail. I assume it would not because the weight vector is always in the negative z direction, but looking at it tells me otherwise...
 
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If the center of mass is not in the center of the box, due to a mass placed offcenter, then there will be a torque about the center (created by gravity), so additional tension on one or two strings (upward) will create an offsetting torque.
 
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scottdave said:
If the center of mass is not in the center of the box, due to a mass placed offcenter, then there will be a torque about the center (created by gravity), so additional tension on one or two strings (upward) will create an offsetting torque.
Thank you
 
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