Does this integral converge or diverge?

[Dell]

the given integral is:

$$\int$$$$\frac{dx}{ln(x)}$$ (from 0 to 1)


now i have a problem at both ends of the integral, because i have ln(0) is undefinde and ln(1) is 0 and 1/0 is undefined, so i can integrate from 0 to 0.5 and 0.5 to 1, but i tried to integrate this and just couldnt, i tried substitution
t=ln(x)
x=e^t
dt=dx/x

and then tried integration in parts but this just didnt work,

so then i thought maybe i need to find a similar function which i know more about or can easily find more about, but again i have problems at both limits, so i think i need 2 separate functions, since i know that 1/ln(x) is negative in the limits 0-1, i will take the abs value of 1/ln(x) and look for positive functions...
i am looking for an integral that is either
*bigger than my original integral and converges
*smaller than my original integral and diverges

what i found was
$$\int$$dx/$$\sqrt{x}$$ (from 0 to 0.4) which converges and is bigger than $$\int$$dx/|ln(x)| (from 0 to 0.4 )

and my second integral is $$\int$$1/x (from 0.6 to 1) which diverges and is smaller than $$\int$$dx/|ln(x)| (from 0.6 to 1 )

therefore i know that the integral $$\int$$$$\frac{dx}{ln(x)}$$ (from 0 to 1) diverges near 1, and converges near 0, so all in all it diverges.

is this okay? is it alright that i didnt take into account the area between 0.4 and 0.6 since the function is constant there anyway??

can you see any better way to solve this??

 

[elect_eng]

is this okay? is it alright that i didnt take into account the area between 0.4 and 0.6 since the function is constant there anyway??

can you see any better way to solve this??

I came to a similar conclusion using your first substitution t=ln|x|. I found this easier to visualize. The lower limit of zero transforms to negative infinity and it is clear that the integral of exp(t)/t converges at negative infinity. However the upper limit of 1 transforms to zero and it is clear that the integral of exp(t)/t diverges at zero, since the numerator goes to unity and the denominator is a divergent 1/t form.