Does This Recursively Defined Sequence Converge?

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SUMMARY

The discussion centers on the convergence of a recursively defined sequence where a1=0.3 and a(n+1)=sqrt(an+1). Participants compute the first five terms and establish that the sequence converges by demonstrating it is increasing and bounded. The limit of the sequence is found through proving that a(n+1) > a(n), specifically by analyzing the condition for √(1 + a) > a.

PREREQUISITES
  • Understanding of recursive sequences
  • Knowledge of limits and convergence in calculus
  • Familiarity with the properties of square roots
  • Basic algebraic manipulation skills
NEXT STEPS
  • Prove that a(n+1) > a(n) for the sequence defined
  • Explore the concept of bounded sequences in calculus
  • Learn about the Monotone Convergence Theorem
  • Investigate the behavior of sequences defined by recurrence relations
USEFUL FOR

Students studying calculus, particularly those focusing on sequences and series, as well as educators looking for examples of convergence proofs in recursive sequences.

workerant
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[SOLVED] Convergence of a Sequence

Homework Statement


Consider the following "recursively defined" sequence:

a1=0.3
a(n+1)=sqrt (an+1)

Compute the first first five terms and prove that it converges. Then, find the limit of the sequence.


Please see:

Problem 3, particularly parts c and d here for the complete problem:

http://rutcor.rutgers.edu/~ngoldberg/math152/ws0837.pdf



The Attempt at a Solution



I would try to show that the sequence is increasing and bounded because that shows that it converges. I am not sure, however, how to go about doing this.

I think I am okay with finding the first five terms. I suppose the second term would be a2= sqrt (a1+1)=sqrt (1.3) and so on and so forth and it would get quite complicated.

I am not sure how to go about the proof and finding the limit.


Thank you.
 
Last edited by a moderator:
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Welcome to PF!

workerant said:
I would try to show that the sequence is increasing and bounded because that shows that it converges. I am not sure, however, how to go about doing this.

Hi workerant! Welcome to PF! :smile:

Do one step at a time!

First step is to prove that a_n+1 > a_n.

In other words, that √(1 + a_n) > a_n

Hint: what is the condition for √(1 + a) > a? :smile:
 

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