Does x<=b Imply max(x)=b and How Do Set Operations Differ?

AI Thread Summary
The discussion centers on the implications of the inequality x <= b and its relationship to the maximum and supremum of sets. It clarifies that while x <= b does not imply max(x) = b, it can be interpreted as the interval (-infinity, b]. The confusion arises from the definition of the supremum, where it is noted that if the supremum is not part of the set, it does not equate to the maximum. An example is given with the set S = [0,1), where the supremum is 1, but there is no maximum. The conversation highlights the nuances in understanding supremum and maximum in set theory.
torquerotates
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If x<=b does this mean max(x)=b?

is x<=b equivalent to the interval (-infinity, b]?
 
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i think so.
 
>If x<=b does this mean max(x)=b?

No.
3 <= 4, but max(3) is not 4. It's only 3.

>is x<=b equivalent to the interval (-infinity, b]?

Yes, assuming x and b can't themselves be -infinity.
 
torquerotates said:
If x<=b does this mean max(x)=b?

is x<=b equivalent to the interval (-infinity, b]?

You need to be more specific about x and b. Is x a constant or an unknown or a variable? b should also be defined as to what kind of thing it is.
 
@math man, x is an unknown while b is a constant. The thing that is confusing me is that my analysis textbook defined the sup of a set, call it S, as having the following property, if s is in S, then s<=sup(S). Now that is confusing bc they didn't specify if sup(S) belonged to S. But s<=sup(S) means that s is in the interval (-infinity, sup(S)] implying max(S)=sup(S). Its as if the defintion of supremum is forcing sup(S) to be the max of S.

So the only way I around it is that if sup(S) not in S, then s<sup(S) => s<=sup(S). Which makes sense because if s is strictly less than sup(S), I think I can say that it is strictly less than or equal to sup(S). Is this line of thinking correct?
 
What they are trying to get at is the following:

Consider the set S = [0,1). What is the sup? Does it have a maximum?
 
The sup is 1 and it has no max. But does s<1 mean s<=1?
 
does s<1 mean s<=1?

Yes. s<1 also means s<2000 and s<=2000.

defined the sup of a set, call it S, as having the following property, if s is in S, then s<=sup(S).

That's a crappy definition. Because then the sup of {1,2,3,4} could be 4, 4.5, 5, or 5000.
The supremum is normally defined as the smallest such possible value; in my example, 4.
 
Sorry I forgot to include that if e>0 then there exists s* s.t
supS-e<s*<=supS.
 
  • #10
wait, so if a<b => a<=b, then why does the same logic not work for sets? for example, why isn't A=AorB. Looking at a venn diagram, we clearly see that the area of the union is greater than the area of A.
 

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