1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Domain and range of multivariable functions

  1. Mar 22, 2015 #1
    1. The problem statement, all variables and given/known data
    Specify the domain and range of f(x, y) = arccos(y − x2). Indicate whether the domain is (i)
    open or closed, and (ii) bounded or unbounded. Give a clear reason in each case.

    2. Relevant equations

    3. The attempt at a solution

    y-x2 >= -1
    y >= x2 -1

    y-x2 <= 1
    y <= x2 +1

    I sketched it and found the region to be in between the two parabolas

    [1;infinity) U [-1;-infinity)

    I don't know if those are correct but I got them from the sketch

    I don't know what (i) and (ii) means
  2. jcsd
  3. Mar 22, 2015 #2


    User Avatar
    Homework Helper

    Recall from real single variate calculus the domain of the ##\text{arccos}(x)## function: ##x \in [-1, 1]##. Notice this is the range of the ##\text{cos}(x)## function.

    So if ##D = \{ x \in \mathbb{R} \space | \space -1 \leq x \leq 1 \}##, the range can be deduced as ##R = \{ y \in \mathbb{R} \space | \space 0 \leq y \leq \pi \}##.

    Most of this translates over to real multivariate calculus. That is, you require the domain to satisfy:

    $$(y - x^2) \in [-1, 1]$$

    So ##D = \{ (x, y) \in \mathbb{R^2} \space | \space -1 \leq y - x^2 \leq 1 \}##.

    Can you deduce the range?

    For (i) and (ii), what does it mean when the domain is open/closed, bounded/unbounded?
  4. Mar 22, 2015 #3
    Is the range 0 <= z <= 180 ?, because if y-x^2 = 1, then the min value of z would be 0 and if y-x^2 had to equal -1 then the max value of z would be 180 so the range would be in between 0 and 180
  5. Mar 22, 2015 #4


    Staff: Mentor

    You should be thinking in terms of real numbers (i.e., radians), not degrees. The range of the arccosine function is [0, ##\pi##].
  6. Mar 22, 2015 #5


    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Education Advisor

    I'm not sure if you were trying to specify a two-dimensional region here, but what you wrote corresponds to the union of two pieces of the number line.

    The way you analyzed it graphically is fine. The notation you would use to describe that region is what Zondrina wrote.

    In math, it's crucial to know the precise definition of various terms as well as what they intuitively mean. If you don't know what a term means, you should look it up — that's the least you can do. If you already did this, you should have said so. If you can't make complete sense of the definition after reading about it, at least you'll have some idea of what it means. You can then ask a specific question about what's confusing you.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted