Doppler Effect of a blown whistle

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SUMMARY

The discussion centers on calculating the Doppler Effect for a whistle with a frequency of 500 Hz, revolving at 400 revolutions per minute (rev/min) on a string of length 1.2 m. The speed of sound is given as 340 m/s. Participants clarify that the length of the string serves as the radius for the circular motion, and the Doppler Effect must be applied to determine the frequency range heard by a listener. The correct frequency range options provided include 436 to 586 Hz, 426 to 574 Hz, 426 to 584 Hz, and 436 to 674 Hz.

PREREQUISITES
  • Doppler Effect principles
  • Understanding of circular motion
  • Conversion of revolutions per minute to radians per second
  • Basic trigonometry for circular motion calculations
NEXT STEPS
  • Calculate the frequency shift using the Doppler Effect formula
  • Convert 400 rev/min to radians per second
  • Determine the velocity of the whistle using the formula v = 2πnr
  • Explore applications of the Doppler Effect in real-world scenarios
USEFUL FOR

Physics students, educators, and anyone interested in understanding the Doppler Effect and its applications in wave mechanics.

lha08
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Homework Statement


A whistle of frequency 500 Hz tied to the end of a string of length 1.2 m revolves at 400 rev/min. A listener standing some distance away in the plane of rotation hears frequencies in the range ____?
(speed of sound=340 m/s)
a) 436 to 586
b) 426 to 574
c) 426 to 584
d) 436 to 674


Homework Equations





The Attempt at a Solution


I'm not really sure how to approach this particular problem...i'm lost especially for the units and what to do with the string...thanks
 
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when the whistle is moving in a horizontal circle, at two points on the circle the whistle is moving either towards the observer or away from him. Apply Doppler effect to find the frequencies.
 
rl.bhat said:
when the whistle is moving in a horizontal circle, at two points on the circle the whistle is moving either towards the observer or away from him. Apply Doppler effect to find the frequencies.

okay i understand that part, but how do i convert 400 rev/min and for the length of the string do i use C=2(pi)radius and solve for r?
 
Last edited:
Velocity v = 2*pi*n*r where n is the number revolution per second.
 
rl.bhat said:
Velocity v = 2*pi*n*r where n is the number revolution per second.

but how do i solve for the radius using the length of the string?
 
lha08 said:
but how do i solve for the radius using the length of the string?
Length of the string itself is the radius.
 

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