1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Doppler shift and change in intensity of a sound wave

  1. Jul 4, 2016 #1
    How are the intensity of a sound wave and the Doppler shift of frequency related togheter?
    That is, if the source or the observer are in relative motion, how does the intensity change?

    For a sound wave $$I=\frac{1}{2} \rho \omega^2 A^2 c=2 \pi^2 \rho f^2 A^2c$$

    (##c## is sound speed, ##\rho## is density of air, ##A## is amplitude)

    So, since Doppler effect is only about ##f##, I would say that

    $$I'=I \bigg(\frac{f'}{f}\bigg)^2=I \bigg(\frac{c+v_{oss}}{c+v_{sorg}}\bigg)^2$$

    But I don't think that this is correct, can anyone give suggestion about this?
  2. jcsd
  3. Jul 5, 2016 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper

    What makes you think this is not correct?
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted