Dot product and cross product problem

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SUMMARY

The discussion revolves around calculating the expression C*(A X 3B) using the vectors A = 4I - 3J - 2K, B = -3I + 1J + 2K, and C = -3I + 5J - 4K. The correct approach involves first computing the cross product A X 3B, where the scalar 3 can be factored out. The final result of the dot product C*(A X 3B) yields the answer of 66, confirming the physics teacher's solution. The calculations involve vector component manipulation and the application of the cross product and dot product formulas.

PREREQUISITES
  • Understanding of vector operations, specifically cross product and dot product
  • Familiarity with vector notation in three-dimensional space (I, J, K components)
  • Knowledge of scalar multiplication of vectors
  • Basic proficiency in multivariable calculus or linear algebra
NEXT STEPS
  • Study the properties of the cross product in vector calculus
  • Learn how to compute dot products of vectors in three-dimensional space
  • Explore scalar multiplication and its effects on vector operations
  • Practice solving problems involving vector operations using different examples
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Students in physics or mathematics, particularly those studying vector calculus, as well as educators looking to clarify vector operations for their students.

tballs
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I am having problems with this questions my physics teacher gave us. Since he doesn't explain things well, I do not know how he got an answer of 66. Can you please explain to me how to get this answer? THX.

For the following three vectors, what is C*(A X 3B) (the "*" is suppose to be a dot)

A = 4I -3J -2K B = -3I +1J +2K C = -3I + 5J -4K

Homework Equations





I J K I J
4 -3 -2 4 -3
-9 3 6 -9 3

(18I+6I) + (18J-24J) + (-27K-12K)
24I - 6J - 39K

(24I X -3I) + (-6J X 5J) + (-39K X -4K)

-72I -30J +156

156-102

54
 
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tballs said:
I am having problems with this questions my physics teacher gave us. Since he doesn't explain things well, I do not know how he got an answer of 66. Can you please explain to me how to get this answer? THX.

For the following three vectors, what is C*(A X 3B) (the "*" is suppose to be a dot)

A = 4I -3J -2K B = -3I +1J +2K C = -3I + 5J -4K

Homework Equations





I J K I J
4 -3 -2 4 -3
-9 3 6 -9 3

(18I+6I) + (18J-24J) + (-27K-12K)
24I - 6J - 39K

(24I X -3I) + (-6J X 5J) + (-39K X -4K)

-72I -30J +156

156-102

54

Do the cross product first, the three in front of B is a constant and can be pulled out of the cross product (or you can multiply three into all of the components of B, either works).

Cross product by components:
(A(J)*(B(K) - B(J)*A(K))I - (A(I)*B(K) - B(I)*A(K))J + (A(I)*B(J) - B(I)*A(J))K

Then dot product is just multiplying each component and summing them.

(A(I)*B(I)) + (A(J)*B(J)) + (A(K)*B(K)) and that should give you a number (or a scalar).

I hope the notation makes sense. A/B then the I, J, or K component of that vector is inside of parentheses.

Have fun with multivariate calc/linear algebra junk
 
thank you I figured it out.
 

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