Double Integral Help: Solving for e^sin(x) over D

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SUMMARY

The discussion focuses on evaluating the double integral of e^sin(x) over the region D defined by 0 ≤ x ≤ π/2 and 0 ≤ y ≤ cos(x). The correct approach involves integrating with respect to y first, leading to the expression y * e^sin(x). The final result of the integral is calculated as e^1 - e^0, which equals approximately 1.718. The participants confirm that the order of integration does not affect the outcome in this case.

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double integral help??

Homework Statement


Evaluate the double integral

| | e^sin(x) dA
over the region
D = {(x,y) | 0 ≤ x ≤ π/2, 0 ≤ y ≤ cosx} .

Homework Equations


The Attempt at a Solution


how would i do this? i know that dA = dy(dx) so the integral would be
|(0 ≤ x ≤ π/2) |(0 ≤ y ≤ cosx) (e^sin(x) dy) dx

would i have to switch the integration? so it would be dx(dy) instead? or could i just integrate it with respect to dy and say it is y*e^sin(x)?
 
Last edited:
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Order of iteration in such a double integral does not matter.

Edit: you're in the right direction.
 
Last edited:
OK, then i guess the rest is easy. i did get y*e^sin(x) when i integrated with respect to dy and my final answer was e1 - e0 = 1.718
 

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