Double Integral Homework: Find Heat in Metal Plate Region x2+y2≥1

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Homework Help Overview

The problem involves calculating the total heat in a metal plate based on a given heat density function, constrained within a specific region defined by inequalities involving x and y coordinates.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the limits of integration for the double integral, with some questioning the correctness of the initial setup and others suggesting potential upper limits for y. There is also a discussion about the method of integration and transformations to simplify the integral.

Discussion Status

The discussion is active, with participants exploring different interpretations of the limits and the integration process. Some guidance has been offered regarding the integration technique, but no consensus has been reached on the overall approach.

Contextual Notes

Participants are navigating constraints related to the defined region of integration and the heat density function, with some expressing uncertainty about the limits and the correctness of the formula provided.

arl146
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Homework Statement


Consider the heat density function for a metal plate: x + y2 + x2

Find the total heat in the plate given that the plate resides in the region x≥0, y≥0, x2 + y2 ≥ 1


The Attempt at a Solution



i thought it was pretty straightforward. i did a double integral with both limits being 0 to 1 but my professor said the y limit is not to 1. what is the top limit then?
 
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arl146 said:
Find the total heat in the plate given that the plate resides in the region x≥0, y≥0, x2 + y2 ≥ 1

Are you sure you copied the last formula correctly? I would mean both x and y going to infinity.

ehild
 
should be less than or equal to 1
 
so is the upper limit of y just sqrt(1-x^2) ?
 
Correct
 
ok now i can't do the integral..first step, integrate WRT y. so the function becomes x + (y^3)/3 + x^2
plugging the limits for y in:

[x + [ (1-x^2)^(3/2) / 3 ] + x^2] - x - 0 - x^2

so youre just left with [ (1-x^2)^(3/2) / 3 ]. how do you integrate that WRT x ??
 
Last edited:
Let [itex]x= sin(\theta)[/itex]. That's a pretty standard integral.
 

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