Double Integral Laws: Moving & Changing Order

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SUMMARY

The discussion centers on the manipulation of double integrals, specifically regarding the ability to change the order of integration and the conditions under which a function can be moved outside the integral. It is established that the integral diverges due to the term \int_{\frac{x-tx}{t}}^{\infty}dy. The function f can be moved outside the integral if it is solely a function of x, treating it as a constant with respect to y. If f depends on y, it must remain within the dy integral for the expression to be valid.

PREREQUISITES
  • Understanding of double integrals and their properties
  • Familiarity with functions of multiple variables
  • Knowledge of integration techniques and convergence criteria
  • Basic calculus concepts, specifically regarding limits and divergence
NEXT STEPS
  • Study the properties of double integrals in calculus
  • Learn about conditions for convergence in improper integrals
  • Explore the Fubini's Theorem for changing the order of integration
  • Investigate functions of multiple variables and their integration
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Mathematicians, calculus students, and educators focusing on advanced integration techniques and the properties of functions in multiple dimensions.

nhrock3
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[tex]\int_{0}^{\infty}fdx\int_{\frac{x-tx}{t}}^{\infty}dy=\int_{0}^{\infty}dx\int_{\frac{x-tx}{t}}^{\infty}fdy[/tex]

f is a function of x and y

can i move f like i showed?

can i change the order of integration
?
 
Last edited:
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As stated, your integral does not exist because the term

[tex]\int_{\frac{x-tx}{t}}^{\infty}dy[/tex]

diverges. To answer your question more generally, yes, you may move f provided it is only a function of x and not of y. In that case f is a constant w.r.t. y, and you may move constants in and out of an integral. If f is a function of y, it *has* to be inside the dy integral - your left-hand integral would not make sense. By the way, I am assuming your integral is intended to be

[tex]\int_{0}^{\infty}f(x) \left( \int_{\frac{x-tx}{t}}^{\infty}dy \right) dx[/tex]
 

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