Double Integral over General Region : Hass Section 13.2 - Problem 5

  • #1

Homework Statement



Outer Integral: From zero to one dy
Inner Integral: from zero to y^2 dx

Function is: 3y^3 * e^(xy)


Homework Equations


None


The Attempt at a Solution



Have tried numerous u substitutions on e^(xy), but taking me nowhere. I am clearly doing something wrong. Assuming 3y^3 is a constant and does not need to be integrated when integrated with respect to x.

Solutions manual shows result of inner integral being [3y^2 * e^(xy)] from zero to y^2 - which appears to me that a y in the original 3y^3 simply disappeared! No idea how they are getting from 3y^3 to 3y^2 as the result of the first integration!

I am quite sure this is an easy problem and I am simply overlooking a very simple step.
 

Answers and Replies

  • #2
fzero
Science Advisor
Homework Helper
Gold Member
3,119
289
You need to use integration by parts.
 

Related Threads on Double Integral over General Region : Hass Section 13.2 - Problem 5

  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
3
Views
988
Replies
9
Views
1K
  • Last Post
Replies
2
Views
586
Replies
4
Views
5K
  • Last Post
Replies
5
Views
8K
Replies
3
Views
2K
Replies
6
Views
3K
  • Last Post
Replies
2
Views
947
Top