Double Integral with Negative Exponent

[Loppyfoot]

Homework Statement

∫4to5 ∫1to2 (1x + y)−2 dy dx

The Attempt at a Solution

I am confused about what to do with this negative 2.

Any ideas?

 

[LCKurtz]

Homework Statement

∫4to5 ∫1to2 (1x + y)−2 dy dx

The Attempt at a Solution

I am confused about what to do with this negative 2.

Any ideas?

An antiderivative of -2 with respect to y is -2y. Or if that -2 is supposed to be an exponent, use the X² button: (x + y)^-2. If that is what you mean then let

u = x + y, du = dy

to proceed.