- #1
Renzokuken
- 14
- 0
1. ∬(4-y^2 )dxdy
bounded region between y^2=2x and y^2=8-2x
I took the integral 4-y^2 dx and got 4x-xy^2 from 0-4 = 16-4y^2
then I took the integral 16-4y^2 dy from -2-2 = 128/3
It is wrong and I don't know what to do.
bounded region between y^2=2x and y^2=8-2x
I took the integral 4-y^2 dx and got 4x-xy^2 from 0-4 = 16-4y^2
then I took the integral 16-4y^2 dy from -2-2 = 128/3
It is wrong and I don't know what to do.