Double Integration to Find Volume

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Homework Statement



Find the volume of the region inside the surface z=x^2+y^2 and between z=0 and z=10

Homework Equations



x^2+y^2=10

The Attempt at a Solution



I know that I have to use some sort of double integration to find this volume, but I'm not really sure where to begin with the problem
 
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[tex]\iiint_V dV[/tex] the upper curve is [tex]z=10[/tex] the lower curve is [tex]z=0[/tex] the area of integration in [tex]\mathbb{R}^2[/tex] is a circle of radius 10. Now use cyclindrical change of variable.
 
hmm...I may try that if I can't find an alternative, but is there any way to do this problem with a double integration and not a triple integration? because the section I'm working with is strictly double integration
 
That's a paraboloid. Since you have "flat" bottom and top I recommend you imagine the solid consisting of thin horizontal pieces. It should be obvious that the piece at height z is a disk satisfying [itex]x^2+ y^2= z[/itex]. What is the area of that disk? If you think of the disk as having thickness "dz", what is its volume? Now "add" the volumes of all those disks.