Doubt from rotational mechanics

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SUMMARY

The discussion focuses on the application of Newton's laws of rotational motion, specifically regarding the calculation of net torque. It is established that net torque can be calculated about any axis, not just the center of mass, provided that the moment of inertia is appropriately considered for that axis. The parallel axis theorem is crucial when calculating moment of inertia for axes that do not pass through the center of mass. Additionally, when performing moment balances about axes other than the center of mass, pseudo forces must be included in the calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with concepts of torque and moment of inertia
  • Knowledge of the parallel axis theorem
  • Basic principles of rotational dynamics
NEXT STEPS
  • Study the application of the parallel axis theorem in rotational dynamics
  • Learn about pseudo forces and their role in non-inertial reference frames
  • Explore advanced problems involving torque calculations about various axes
  • Review the derivation and implications of the equation ##\tau = I\alpha## in different contexts
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Students of physics, mechanical engineers, and anyone studying rotational mechanics who seeks to deepen their understanding of torque and moment of inertia calculations.

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in Newton's laws of rotational motion,
is the net torque calculated only about centre of mass?or is it valid for torque about any axis?
 
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For the mass to rotate about any point that is not the centre of mass, there would have to be another external force involved.

As for axes of rotation, a long thin strip of a mass would have a different torque along different axes. Very easy to flip a 2x4 along its long axis (twirling it). Not so easy to flip it along its short axes (end-over-end).
 
DaveC426913 said:
For the mass to rotate about any point that is not the centre of mass, there would have to be another external force involved.

As for axes of rotation, a long thin strip of a mass would have a different torque along different axes. Very easy to flip a 2x4 along its long axis (twirling it). Not so easy to flip it along its short axes (end-over-end).
thank you very much sir,but i couldn't really understand your reply.please be little elaborate,i know that Newton's law for rotation can be applied to center of mass but in a problem,Newton's law of rotation was applied about an hinge.i couldn't understand this,please explain,why is it so?
 
It is possible to use the rotational analogue of Newton's law, just be careful of the Moment of Inertia that you use in your equations. The Moment of Inertia must be taken about the rotation axes.

Also, if I'm not wrong, ##\tau = I\alpha ## holds only if the axis is fixed. The only exception is if the torque and moment of inertia I are computed about the centre of mass, then the above relation holds if the object is translating with acceleration.
 
thank you very much for replying,sir.

sir,if we are considering a disc hinged to a rod perpendicular to the plane of disc but it is intersecting the disc at some other than centre,can we still use Newton's law for rotation,if yes then what are the axes about which we can apply this law?and about what axis should torque,moment of inertia and angular acceleration be measured?
 
Yes you can still use Newton's Law. It would be most useful to consider the torque about the rotation axis, which would passing through the hinge in your question.
So net torque, ##\sum\tau = F\times r = I\alpha## .

In the above equation, everything should be taken with respect to the rotation axis. This includes the moment of inertia I like I was saying in my previous post. So do remember to apply the parallel axis theorem in this case.
 
JeremyG said:
Yes you can still use Newton's Law. It would be most useful to consider the torque about the rotation axis, which would passing through the hinge in your question.
So net torque, ##\sum\tau = F\times r = I\alpha## .

In the above equation, everything should be taken with respect to the rotation axis. This includes the moment of inertia I like I was saying in my previous post. So do remember to apply the parallel axis theorem in this case.
thank you sir,it cleared my doubt.
 
Not so fast. It you're doing the moment balance about anything other than the center of mass, you need to include pseudo forces (-ma) in the moment balance. It's always safest to do the moment balance about the center of mass.
 
Chestermiller said:
Not so fast. It you're doing the moment balance about anything other than the center of mass, you need to include pseudo forces (-ma) in the moment balance. It's always safest to do the moment balance about the center of mass.
sir,can you please illustrate your point in above example.
 

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