Doubts in double slit experiment

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Constructive interference occurs when the path difference is a multiple of the wavelength, yet the central maxima is the brightest due to the intensity distribution from the slits. Each slit acts as a source of wavefronts, creating a diffraction pattern influenced by the sinc^2 profile, which leads to a pronounced central peak. The brightness of fringes decreases with increasing n because the amplitude of the waves that interfere constructively varies with distance from the slits. This phenomenon is explained by the Huygens-Fresnel principle, where the central maximum results from the closest proximity to the light sources. Understanding these principles clarifies why the central fringe is the brightest and why other fringes exhibit reduced brightness.
journeytospace
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hi all...it is said that constructive interference happens when the path difference is nlambda and i think wavelength,frequency and amplitude of light going through both slits is the same then
why is the central maxima is the brightest spot?
why the brightness decreases when n increases?

Since the amplitude is same why there is difference in the brightness of the bright fringes?
 
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Because the amplitudes of the waves that constructively interfere are different at 'different n'.
 
why does the amplitude changes and why the central fringe is the brightest one(why not other fringes)..can u explain in detail about it?..
 
Each of the slits acts as a radial light source (in the right half of the plane). You can think of it like this: Lines of equal field intensity are semi-circles. The intensity at a point on the circle is inversely proportional to its size, or in other words its distance from the point source. Now if you draw the screen, the screen's center is on a smaller circle (drawn around the source) than a point further away is.
 
journeytospace said:
hi all...it is said that constructive interference happens when the path difference is nlambda and i think wavelength,frequency and amplitude of light going through both slits is the same then
why is the central maxima is the brightest spot?
why the brightness decreases when n increases?

Since the amplitude is same why there is difference in the brightness of the bright fringes?

This has nothing to do with quantum mechanics. I'm moving it out of there.

Zz.
 
The diffraction pattern of a double-slit is a actually a convolution between the characteristic sinc^2 single-slit pattern that has a bright central peak and secondary peaks at either side of the central peak, and the characteristic cos^2 fringes.

The finite number of visible peaks comes about because of the finite width of the slits. As one reduces the width of the slits, the diffraction pattern will approach the ideal cos^2 case.

trinitron said:
Each of the slits acts as a radial light source (in the right half of the plane).
This is wrong, slits don't act like point sources, they have a characteristic sinc^2 emittance profile. The reason the brightest fringe is in the centre is for the same reason single-slit diffraction has a bright central peak - it all boils down to the Huygens-Fresnel principle of secondary wavelets.

Claude.
 
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