Drag Coefficient out by a factor of 10, can anyone help?

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SUMMARY

The discussion centers on calculating the drag coefficient for a sphere using experimental data. The user measured a drag force of 0.68N at a wind speed of 7.8m/s and a sphere radius of 0.0371m, leading to an unexpected drag coefficient of 5.039. The correct formula used is Drag coefficient = (2 x Drag) / (Area x Wind Speed^2 x Density of Air), with the density of air taken as 1.204kg/m^3. A suggestion was made to verify the accuracy of the drag force measurement and the units used in the wind tunnel readings.

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Drag Coefficient out by a factor of 10, can anyone help??

Im doing an experiment on the drag of a sphere and am trying to work out the drag coefficient. From looking at data online this should be around 0.5 (its a smooth sphere). Using a wind tunnel I measured the drag for various sizes of spheres and wind speeds. An example of one of my results is

Drag - 0.68N
Wind Speed - 7.8m/s
Radius of Sphere - 0.0371m

Then, using the formula

Drag coefficient = (2 x Drag) / Area x Wind Speed^2 x Density of Air

Having measured the room temperature to be 22 degrees celsius I took the density of air to be 1.204kg/m^3 and the projected frontal area was calculated using pi x r^2

But this equals 5.039! so could anyone point out where I am going wrong?? I am 90% sure all of my values are correct. Thanks in advance for any help :)
 
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Are you absolutely sure about the calculated drag force? Your equation is correct, although I get 4.293 when I plug your data into it (probably rounding differences). I'm not terribly familiar with wind tunnels, but try checking the units of the readings that you're getting from it.
 

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