Drawing the angular velocity graph from the acceleration vs. time graph?

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To draw the angular velocity graph from the given angular acceleration vs. time graph, the area under the acceleration curve must be calculated for specific time intervals. The area from t=0 to t=1 yields an angular velocity of 2.5 m/s, but the plotting tool only accepts whole numbers, complicating the graphing process. Users are advised to round the value to the nearest whole number for plotting purposes. If calculus is permitted, the relationship between angular acceleration and velocity can be expressed through integration, allowing for a more precise graph. Understanding these concepts is crucial for accurately representing the angular velocity over time.
mymabelline
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1. So this is one of my homework problems and I just can't seem to get it, and my attempts are verging on pathetic. I feel like this shouldn't be this hard, maybe I'm just missing something. This is the acceleration vs. time graph: http://session.masteringphysics.com/problemAsset/1070314/6/04.EX33.jpg and the question it is asking is :The figure shows angular acceleration versus time. Draw the corresponding graph of angular velocity versus time. Assume omega _0 = 0
Please help, I never took physics in high school and right now physics is making my head feel like somebody hit me with a bat.

 
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If you are not able to use calculus, then the fact that the area under the angular acceleration vs. time graph gives the angular velocity.

So if you find the area from t=0 to t=1, you will get the angular velocity at t=1. So just find the areas for different ranges and then plot the graph. Note how the slope of the angular acceleration graph changes at t=2.
 
rock.freak667 said:
If you are not able to use calculus, then the fact that the area under the angular acceleration vs. time graph gives the angular velocity.

So if you find the area from t=0 to t=1, you will get the angular velocity at t=1. So just find the areas for different ranges and then plot the graph. Note how the slope of the angular acceleration graph changes at t=2.

I tried doing that, but on the y axis, which is angular velocity I can only plot whole numbers, and finding the area under the curve from t=0-t=1 gives me an area of 2.5
 
mymabelline said:
I tried doing that, but on the y axis, which is angular velocity I can only plot whole numbers, and finding the area under the curve from t=0-t=1 gives me an area of 2.5

Why do you need to plot whole number for? Although the calculus approach would be much easier, are you allowed to use calculus to draw the graph?
 
rock.freak667 said:
Why do you need to plot whole number for? Although the calculus approach would be much easier, are you allowed to use calculus to draw the graph?

I am allowed to use calculus, what I was saying is that the velocity i find for t=1 is equal to 2.5 m/s and the online graph that they have given to me to plot my results only allows me to plot (1,2) or (1,3), not (1,2.5) like i need
 
mymabelline said:
I am allowed to use calculus, what I was saying is that the velocity i find for t=1 is equal to 2.5 m/s and the online graph that they have given to me to plot my results only allows me to plot (1,2) or (1,3), not (1,2.5) like i need

In that case you might need to round up to 3.

But if you can use calculus, then for t=0 to t=2, you can see that gradient of the ang. acc. vs. t graph is 2, meaning that the equation of that section is α=2t and since ω=∫α dt, then you can get how 'ω' will look for that range.
 
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