Drawing the angular velocity graph from the acceleration vs. time graph?

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Homework Help Overview

The discussion revolves around a homework problem related to drawing an angular velocity versus time graph from a given angular acceleration versus time graph. The original poster expresses difficulty in understanding the problem, particularly due to a lack of prior physics education.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between angular acceleration and angular velocity, noting that the area under the acceleration graph corresponds to velocity. Some participants suggest calculating areas for specific time intervals to plot the velocity graph.

Discussion Status

There is an ongoing exploration of how to handle the plotting of angular velocity, particularly regarding the need to round values to whole numbers for graphing purposes. Some participants have offered guidance on using calculus to derive the angular velocity from the acceleration graph.

Contextual Notes

The original poster mentions restrictions in the online graphing tool that only allows whole number values, which complicates the plotting of calculated velocities. There is also a question about the permissibility of using calculus in the problem-solving process.

mymabelline
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1. So this is one of my homework problems and I just can't seem to get it, and my attempts are verging on pathetic. I feel like this shouldn't be this hard, maybe I'm just missing something. This is the acceleration vs. time graph: http://session.masteringphysics.com/problemAsset/1070314/6/04.EX33.jpg and the question it is asking is :The figure shows angular acceleration versus time. Draw the corresponding graph of angular velocity versus time. Assume omega _0 = 0
Please help, I never took physics in high school and right now physics is making my head feel like somebody hit me with a bat.

 
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If you are not able to use calculus, then the fact that the area under the angular acceleration vs. time graph gives the angular velocity.

So if you find the area from t=0 to t=1, you will get the angular velocity at t=1. So just find the areas for different ranges and then plot the graph. Note how the slope of the angular acceleration graph changes at t=2.
 
rock.freak667 said:
If you are not able to use calculus, then the fact that the area under the angular acceleration vs. time graph gives the angular velocity.

So if you find the area from t=0 to t=1, you will get the angular velocity at t=1. So just find the areas for different ranges and then plot the graph. Note how the slope of the angular acceleration graph changes at t=2.

I tried doing that, but on the y axis, which is angular velocity I can only plot whole numbers, and finding the area under the curve from t=0-t=1 gives me an area of 2.5
 
mymabelline said:
I tried doing that, but on the y axis, which is angular velocity I can only plot whole numbers, and finding the area under the curve from t=0-t=1 gives me an area of 2.5

Why do you need to plot whole number for? Although the calculus approach would be much easier, are you allowed to use calculus to draw the graph?
 
rock.freak667 said:
Why do you need to plot whole number for? Although the calculus approach would be much easier, are you allowed to use calculus to draw the graph?

I am allowed to use calculus, what I was saying is that the velocity i find for t=1 is equal to 2.5 m/s and the online graph that they have given to me to plot my results only allows me to plot (1,2) or (1,3), not (1,2.5) like i need
 
mymabelline said:
I am allowed to use calculus, what I was saying is that the velocity i find for t=1 is equal to 2.5 m/s and the online graph that they have given to me to plot my results only allows me to plot (1,2) or (1,3), not (1,2.5) like i need

In that case you might need to round up to 3.

But if you can use calculus, then for t=0 to t=2, you can see that gradient of the ang. acc. vs. t graph is 2, meaning that the equation of that section is α=2t and since ω=∫α dt, then you can get how 'ω' will look for that range.
 

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