Dropping meat on weighing scale

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Homework Help Overview

The discussion revolves around a physics problem involving a piece of meat dropped onto a weighing scale with a spring mechanism. The participants explore the dynamics of the impact, the energy transformations involved, and the initial compression of the spring when the meat lands on the plate.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy and momentum to analyze the impact of the meat on the plate and the subsequent compression of the spring. Questions arise regarding how to account for the mass of both the meat and the plate in the energy equations, as well as the correct interpretation of potential and kinetic energy in this context.

Discussion Status

The discussion is active, with participants offering various perspectives on the equations involved and questioning the assumptions made about potential energy and kinetic energy. Some guidance has been provided regarding the relationship between the masses and the energy transformations, but there is no explicit consensus on the final formulation of the equations.

Contextual Notes

Participants are navigating the complexities of dynamic versus static scenarios, particularly in relation to how the spring behaves under impact conditions. There is an emphasis on avoiding double counting energy terms and clarifying the definitions of variables used in their equations.

quietrain
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hi, if we drop a piece of meat say 1kg from 1m above the plate, on a plate 2kg, and the plate is on a weighing scale of spring F=kx, how do we find how much the spring will first compress? ( not referring to the equilibrium where total weight = spring force)

so we can't use F=kx = mg here because the mg is for the piece of meat only, but how do i take into account the plate?


and even without the plate, when i first drop the meat from height 1m above the scale, the spring will still compress more than when it reaches equilibrium (mg=kx). so how do i find this initial compression ?

thanks
 
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Using conservation of energy,

The loss in Potential energy of the meat and plate as the spring compress = gain in elastic potential energy of the spring.
 
quietrain said:
so we can't use F=kx = mg here because the mg is for the piece of meat only, but how do i take into account the plate?
In the case of two objects (meat and plate) that impact and don't bounce apart, you can use conservation of energy and also the conservation of momentum to determine the velocity of the pair immediately after impact. Once they impact and move together with a new initial velocity, you can then apply conservation of energy to the pair of objects and compare it to the spring energy.
 
A good engineering rule of thumb is that a dynamic strain is twice the static strain of the same load. Your load will be even higher than that since you are not only applying the strain dynamically, but with some initial kinetic energy.
 
ok, so my equation is now mgh + 1/2mv^2 = 1/2 kx^2

but my m in mgh is the meat only? and h is the height above the plate?

my m in KE is meat + plate? v is final speed determined from conservation of momentum?

and so my x is the initial compression due to the impact?
 
the mgh in ur context is wrong. You are double counting the loss in PE since you already took into account the Kinetic energy arised from the loss in PE
 
oh. so my equation should be just 1/2mv^2 = 1/2kx^2 ?

where m is the total mass ??
 
Looks right to me.
And v is the speed just after the meat lands (1/3 of the meat speed).
 
ah ok thanks everyone
 

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