Dynamical Magnetism Faradays Law

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SUMMARY

The discussion centers on calculating the induced voltage between two parallel loops in a magnetic field, specifically using Faraday's Law of Electromagnetic Induction. The fixed loop has a radius 'a' and resistance 'R', while the moving loop has a radius 'r' and velocity 'v'. The magnetic field 'B' is defined as B = (UIr^2) / (2x^3), leading to the flux through the fixed loop as Flux = Bπa^2. The induced voltage is derived from the rate of change of flux, resulting in Voltage = (πa^2UIr^2 * 3x^-4 * v) / 2. The discussion highlights the need for additional parameters, specifically 'I' (current) and 'x' (distance), to fully solve the problem.

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moo5003
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Problem:

A fixed loop with Radius a and Resistance R is parrallel with the y-z plane. Another loop with radius r parallel to the y-z plane and a distance away from the other loop has a velocity v moving toward the other loop.

What is the induced Voltage?

Assuming (Told to assume this) a << r << x (Distance between loops)

B = (UIr^2) / (2x^3) <--- Taken from physics book

Flux = Integral B * n dA = Bpiea^2. (Flux thru fixed loop)

Voltage = d(Flux)/dt = -piea^2d(B)dt = -(piea^2UIr^2)/2 d(1/x^3)/dt

Problem... d(1/x^3)/dt = -3x^-4*v... I wasnt given x so how do I solve this?

Voltage = (pie*a^2*U*I*r^2*3x^-4*v)/2 (I'm not given I or x) What am I doing wrong here.
 
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please take notice. I am dumb at physics... but from ur questions i see like 3 lines of equations(i don't know if they r related) . Like in maths question like that i would try solve it by simultaneously.
 
Induced voltage in what? Also, there is no B field mentioned in the problem statement, so there is no reason for there to be an induced voltage in anything. Is there a current flowing in the fixed loop, and you're asked to find the voltage induced in the second loop?
 

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