Discovering Force: Acceleration with a Meter Stick at 30° Angle

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To determine the force required to accelerate a hole punch at 9.98 m/s² using a meter stick at a 30° angle, it's essential to understand the components of the force acting along the incline. The force can be broken down into its horizontal and vertical components, with the angle affecting the calculations. The hypotenuse of the force vector is crucial for resolving these components. Participants express confusion about how to approach the problem without clear guidance on calculating the hypotenuse force. Clarification on the problem setup and the application of trigonometric functions is needed to proceed.
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What force pushing with a meter stick, ( theta= 30) will make a hole punch accelerate at 9.98m/s^2?

I am lost cause I don't see what I can do without the hypotnuse force, i just need help to get started i think
 
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Larrytsai said:
What force pushing with a meter stick, ( theta= 30) will make a hole punch accelerate at 9.98m/s^2?

I am lost cause I don't see what I can do without the hypotnuse force, i just need help to get started i think

Hi Larrytsai! :smile:

I'm completely confused. :confused:

Can you describe the problem in a little more detail? :smile:
 

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