Dynamics-Critical Damping Coefficient

Click For Summary

Discussion Overview

The discussion centers around the critical damping coefficient in damped single degree of freedom systems, specifically how the expression for the critical damping coefficient is derived and its implications on oscillation behavior.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant seeks clarification on how the expression for the critical damping coefficient, defined as 2 x m x (omega), is derived, questioning whether it comes from experiments or statistics.
  • Another participant asserts that if the critical damping coefficient is reached, the spring will not oscillate, leading to a discussion about the implications for oscillation frequency.
  • Further contributions explore the relationship between damping coefficient and oscillation frequency, with one participant providing a formula for the damped oscillation frequency and another stating the condition for zero oscillation frequency.

Areas of Agreement / Disagreement

Participants generally agree on the behavior of the system at critical damping, but there is no consensus on the derivation of the critical damping coefficient or the methods used to obtain it.

Contextual Notes

Participants reference various parameters such as mass, natural frequency, and stiffness, but the discussion does not resolve the assumptions or definitions underlying these terms.

Who May Find This Useful

This discussion may be useful for students or professionals interested in dynamics, particularly those studying damped systems and critical damping behavior.

jrm2002
Messages
54
Reaction score
0
I have been reading Equations of Motion pertaining to "Damped Single Degree of Freedom Systems"

There, the critical damping coefficient wherein the oscillation is completely eliminated from the system is defined by:

Critical Damping Coefficient = 2 x m x (omega)

where,
m=mass
omega=natural frequency of the system
Natural frequency of the system= square root(k/m)

k=stiffness of the system

I want to know how the expression for critical damping coefficient obtained as 2 x m x (omega).

Is it obtained through experiments/statistics??

Please help
 
Physics news on Phys.org
Remember how a spring acts if the "critical damping coefficient" is obtained.
How is the spring moving then?
 
Thanks for the response!
The spring will not oscillate if the critical damping coefficient is obtained.
My question is how the expession of

Critical Damping Coefficient = 2 x m x (omega) is obtained??
Is it through experiments or statistics??

where,
m=mass
omega=natural frequency of the system
Natural frequency of the system= square root(k/m)

k=stiffness of the system
 
"The spring will not oscillate if the critical damping coefficient is obtained.
"

Correct!
So, if the system doesn't oscillate, what is its oscillation frequency equal to?
 
if the system does not oscillate , oscillation frequence is zero
 
Again correct!

1. Now, for a given damping coefficient b, what is the general expression for the oscillation frequency of the system?

2. How should we choose critical damping coefficient b* so that the oscillation frequency is, indeed, 0?
 
1)for a given damping coefficient b, what is the general expression for the oscillation frequency of the system,

omegad = omegan x sqrt (1-(b^2/2 x m x (omegan)^2))
2)to keep the oscilaltion "zero"
b=2 x m x (omegan)
 
Again correct. You're finished.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 131 ·
5
Replies
131
Views
9K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
17
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 0 ·
Replies
0
Views
335