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Dynamics of a particle moving in a straight line

  1. May 4, 2013 #1
    Hi all,

    Sorry if I have posted in the wrong place. I am not to familiar with the forum titles and new setting. I have an argument and this is not homework.

    Suppose two particles P and Q of masses 2m and m respectivily are attached to the ends of a light inextensible string which passes over a smooth fixed pulley. They both hang at a distance of 2m above the horizontal ground. The system is released from rest.

    Given that particle Q does not reach the pulley, Find the greatest height that Q reaches above the ground.

    I know how to find final velocities, decelerations etc through the system for each particle. I have got a total distance of 4.66m, however the answer is 2.66 which I am thinking is wrong.

    Since both particles hung 2m above ground Q will be at a distance of 4m as soon as P hits the ground and then continue a small distance of 0.665m during the deceleration span due to the tension in the string.

    Am I right.

    Thank you.
     
  2. jcsd
  3. May 4, 2013 #2

    jbriggs444

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    Science Advisor

    Your answer sounds correct to me.

    As you point out, particle P hits the ground when particle Q is 2 meters above its starting position. That puts Q 4 meters above ground.

    At that point Q had been accelerating through 2 meters with an upward acceleration of 1/3 gravity. It continued upward with a downward acceleration of 1 gravity. Equating the work done on particle Q in the two phases and solving, you get 2/3 of a meter of additional travel for a total of 2.66 meters travel ending 4.66 meters above ground.
     
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