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A particle starts moving from the position

r= -2i+j

with its velocity given as a function of time, t, as

v=(5t^2)i+2j

.

What is the distance of the particle from the origin at time t = 10 s?

The i's a j's both have hats if that makes any difference.

My attempt:

distance = velocity x time

so multiply the v equation by t and then subsitute 10s into it.

This will give the distance travelled in both the x and y direction add these values to the values given in the first equation.

So (5t^2)*t + t*2j

then sub in 10 and add the i and j values to their respective values in the first equation to find the final displacement.

I'm unsure if this is correct or not.

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# Homework Help: Dynamics with complex equations

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