Problem: A particle starts moving from the position r= -2i+j with its velocity given as a function of time, t, as v=(5t^2)i+2j . What is the distance of the particle from the origin at time t = 10 s? The i's a j's both have hats if that makes any difference. My attempt: distance = velocity x time so multiply the v equation by t and then subsitute 10s into it. This will give the distance travelled in both the x and y direction add these values to the values given in the first equation. So (5t^2)*t + t*2j then sub in 10 and add the i and j values to their respective values in the first equation to find the final displacement. I'm unsure if this is correct or not.