E=d/dt(NBAcostθ) Magnetic Field Induced by Rotating Wire in Uniform Field

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SUMMARY

The discussion focuses on calculating the average induced voltage in a rotating wire within a uniform magnetic field using Faraday's Law. The parameters include a 20-turn wire with a surface area of 400 cm², a magnetic field strength of 0.3 T, and a rotation speed of 10 Hz. The calculated induced voltage was found to be 9.6 V, but the user questioned the accuracy of their solution, particularly regarding the rotational speed's influence on the induced voltage. The correct formula to apply is E = d/dt(NBAcos(ωt)), where θ = ωt.

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  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of angular velocity and its relationship to rotational motion
  • Familiarity with basic electrical concepts such as voltage and magnetic flux
  • Ability to convert units, specifically from cm² to m²
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  • Study the application of Faraday's Law in different electromagnetic scenarios
  • Learn about angular velocity and its calculation in rotating systems
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  • Investigate the effects of varying rotational speeds on induced electromotive force (EMF)
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Homework Statement



A 20 turn wire that has a surface of 400cm^2 is rotating around an axe and is at a right angle to a uniform magnetic field of 0.3T. Find the average magnetic field induced if the speed of the rotation is 10 rotations/second.


Homework Equations



Faraday's Law


The Attempt at a Solution



A = 400cm^2 = 0.04m^2
N = 20
B = 0.3T
f = 10Hz



V =(Nxdelta phi)/delta t
B = phi/A
phi = BA = 0.3x0.04 = 0.012wb
V= (20x0.012)/0.1 = 2.4 Volts


Answer = 9.6 V

Can anyone point out where my error is? If there isn't any its possible the answer is wrong.
 
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you did not include the rotational speed

E=d/dt(NBAcostωt)

remember θ=ωt
 

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