- #1

Linus Pauling

- 190

- 0

**1. Two 10-cm-diameter charged rings face each other, 19.0 cm apart. Both rings are charged to + 50.0 nC. What is the electric field strength at the center of the left ring?**

**2. E = q/(4*pi*epsilon*r**

^{2}**3. Ok, the E field from the left ring is zero at this point due to cancellation/symmetry. Using r = 0.19 cm in the above equation, I obtain 1.25*10**

^{4}N/C, but the correct answer is 1.13*10^{4}. What am I doing wrong?