Electric Field Between Two Charged Rings: Problem Solved

  • Thread starter Thread starter Linus Pauling
  • Start date Start date
  • Tags Tags
    E-field Rings
Click For Summary

Homework Help Overview

The problem involves calculating the electric field strength between two charged rings, specifically at the midpoint between the rings and at the center of one of the rings. The context is within electrostatics, focusing on the behavior of electric fields generated by charged objects.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the applicability of treating the rings as point charges and question the symmetry of the electric field at various points. There is also an exploration of the implications of charge distribution and the resultant electric field due to both rings.

Discussion Status

There is a productive exploration of the symmetry in the electric field configuration, with some participants suggesting that the electric field at the midpoint and the center of one ring may be zero due to this symmetry. Others are considering the contributions from both rings and the implications of uniform charge distribution.

Contextual Notes

Participants note potential confusion regarding the treatment of the rings as point charges due to their size relative to the distance between them. There is also mention of the need for physical intuition in understanding the electric field behavior in this symmetrical setup.

Linus Pauling
Messages
187
Reaction score
0
1. Two 10-cm-diameter charged rings face each other, 19.0 cm apart. Both rings are charged to + 50.0 nC. What is the electric field strength:

At the midpoint between the two rings? At the center of the left ring?




2. E = q/4pi*ep_o*r^2



3. The online problem says this is from a certain chapter in our book... that chapter (which we've read) is about point charges. Am I able to treat these things as point charges? I would think not given the small distances being considered... so think maybe it's a typo. Anyways, could someone outline the strategy for this type of problem?
 
Physics news on Phys.org
Is the answer zero in both cases? Since they're both positively charged, the field lines will point into the space between the rings, but then curve upwards as they come together since they're the same sign, so the middle is zero? Likewise, the center of one ring is zero because the y component of the field from that ring cancels out?
 
The field at the midpoint is 0 because of the symmetry of the configuration. Likewise, the field at the center of a ring due to that ring is 0, again due to symmetry. You still have to consider the electric field produced by the other ring, which isn't 0.
 
Well, if I remember, the field at a point is the force experienced by unit charge at the point so they could say point charges come into it, haw haw.

This one is asking for a minimum of physical intuition I guess. The first problem is very symmetrical. As preliminary, a still simpler situation, what is the net result force on a charge just half way between to equal point charges (both of the same sign)?

Moving on to the rings, you can assume the distribution of charge is uniform around the ring. Makes a very symmetrical situation.

In the second problem, the field is (still) the (vector, i.e. directional) sum of the field due to the two different rings. That from the ring it's in the centre of is an extremely symmetrical situation.

3/4 of the question requires no calculation really. :wink:
 
2 other posts came in whilst I was typing mine. If you mean to say points equally distant from equal charges the field is zero, agreed.

Agree field from ring in its centre is zero. So that leaves you with only the second part of the second problem.
 

Similar threads

Replies
4
Views
4K
Replies
11
Views
4K
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 68 ·
3
Replies
68
Views
8K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
9
Views
3K