asdf1
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why does e^[i(phi)] * e^[-i(phi)]=1 instead of e^[(phi)^2]?
E-Powers Homework Help: Understanding Why e^[i(phi)] * e^[-i(phi)] = 1
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Well for powers, so for e-powers in particular, we have that [itex]e^a \cdot e^b = e^{a + b}[/itex]. Applying that here gives e^0 which is of course 1.
asdf1
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thank you very much!
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No problem 