# E^(t^2) i solved it, but can you verify please?

• seto6
In summary, the solution for E^(t^2) is e^(t^2). This is achieved by using the exponential rule, e^(a+b) = e^a * e^b, to simplify the expression. E^(t^2) is a common equation in science, particularly in fields such as physics and mathematics. It is used, for example, in quantum mechanics to calculate the probability distribution of a particle's position over time.
seto6

## Homework Statement

so this is the problem:

## Homework Equations

The fundamental therom of calculus: http://mathworld.wolfram.com/FundamentalTheoremsofCalculus.html

## The Attempt at a Solution

here is what i did, is this valid to do so. {sorry for being large}

as you can see i derived both sides to get that.:::::::

It looks fine, except you aren't finding the integral. You are finding the DERIVATIVE of the integral. Try to be clear on that.

## 1. What is the solution for E^(t^2)?

The solution for E^(t^2) is e^(t^2).

## 2. How did you solve E^(t^2)?

I used the exponential rule, e^(a+b) = e^a * e^b, to simplify E^(t^2) to e^(t^2).

## 3. Can you explain the steps for solving E^(t^2)?

Sure, first I rewrote E^(t^2) as e^(t^2). Then I used the exponential rule, e^(a+b) = e^a * e^b, to simplify the expression to e^(t^2).

## 4. Is E^(t^2) a common equation in science?

Yes, E^(t^2) is a common equation in science, particularly in fields such as physics and mathematics.

## 5. Can you provide an example of how E^(t^2) is used in science?

One example is in the field of quantum mechanics, where E^(t^2) is used to calculate the probability distribution of a particle's position over time.

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