(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Is y = x^2 a solution to the DE [tex]y'' - 4xy' + 4y = 0[/tex]

3. The attempt at a solution

So:

[tex]y = x^2[/tex]

[tex]y' = 2x[/tex]

[tex]y'' = 2[/tex]

[tex] 2 - 4x(2x) + 4x^2 = 0[/tex]

[tex] 2 - 8x^2 + 4x^2 = 0[/tex]

[tex] 2 - 4x^2 = 0[/tex]

But doing this I won't get an answer of whether it is a solution or not. I get a variable equal to a number. So what can I do differently? How do I solve this? Thanks in advance.

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# Homework Help: Easy Differential Equation Calc 1

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