Easy problem, but no idea how to solve it?

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SUMMARY

The discussion focuses on calculating the stopping distance of a car traveling at 60 km/h, given that a motorbike traveling at 40 km/h stops at a distance D with maximum deceleration. The key equation used is v² - u² = 2as, where u is the initial velocity and v is the final velocity. By determining the deceleration 'a' in terms of D from the motorbike's stopping distance, one can apply the same equation to find the stopping distance for the car. This method provides a clear and structured approach to solving the problem.

PREREQUISITES
  • Understanding of kinematic equations, specifically v² - u² = 2as
  • Basic knowledge of velocity and acceleration concepts
  • Ability to manipulate algebraic equations
  • Familiarity with units of measurement (km/h to m/s conversion)
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics
  • Learn about maximum deceleration and its implications in real-world scenarios
  • Explore unit conversion techniques, particularly for speed (km/h to m/s)
  • Practice solving similar problems involving stopping distances and deceleration
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Students studying physics, particularly those focusing on kinematics, as well as educators looking for problem-solving strategies in motion-related topics.

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Homework Statement


A motorbike with the velocity 40km/h is able to stop at a distance, D, when it brakes with maximal deacceleration. At what distance will a car with a velocity of 60 km/h stop?


Homework Equations




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The Attempt at a Solution


I was trying to solve it through regular equations such as at^2=distance, but there seems to be too many unknowns. Any ideas?
 
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Use v^2 - u^2 = 2as. Find a in terms of D. Here u = 40 km/hr and v = 0. Use this a and find the distance for 60 km/hr using the above equation.
 

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