Easy question has me confused (Inclined plane)

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Homework Help Overview

The discussion revolves around a physics problem involving an inclined plane, where a 10 lb block slides down at a constant velocity at an angle of 30°. The task is to determine the block's acceleration when the angle is increased to 45°.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the block, including gravitational components and the role of friction. There is confusion regarding the interpretation of weight as force versus mass, and how to apply the conditions at 30° to find the acceleration at 45°.

Discussion Status

Multiple interpretations are being explored, particularly regarding the necessity of accounting for friction despite it not being explicitly mentioned in the problem statement. Some participants suggest using the conditions at 30° to derive the coefficient of friction, while others express uncertainty about their calculations.

Contextual Notes

Participants note that the problem may be misleading due to the lack of explicit mention of friction, which complicates the solution process. There is a consensus that the 30° condition is significant for determining frictional forces, although the exact nature of the problem remains unclear.

jamesweston0
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It seems to be an easy question but for some reason I can't figure it out.

Homework Statement



2vbsw2x.jpg


If the 10 lb block A slides down the plane with a constant velocity when θ = 30°, determine the acceleration of the block when θ = 45°.

Homework Equations



F = ma

The Attempt at a Solution



I actually am very puzzled by this question. I know that acceleration = 0 at 30° but I don't know how to make use of it. I tried setting the parallel force at 45° to equal ma, then solve for a, but that didn't do it either. Any insight? Thanks.
 
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first resolve the forces around the block
 
FNormal = 10cosθ
Fparallel = 10sinθ

Just sub in 30 and 45 for θ.

What else is there to use?
 
where is gravity in your equation remeber its the force of the block acting down the slope not the mass. Just want to check do you assume that the plane is smooth?
 
Well the 10sinθ is the force of gravity down the ramp. Also, yes I'm assuming the plane is smooth. It doesn't say anything to lead me to believe there's friction.
 
it should be the force of the block acting down the ramp so 10gsin45=ma

but since the mass is the same
should get gsin45=a
 
Hmm I though 10lb is referring to a force not a mass in this case.

Regardless, gsin45 = a is not working out.

32.2sin45 = 22.77 ft/s^2

The real answer is 9.62 ft/s^2.
 
hmmm not sure then. ill have another look
we both must be missing something obvious :/
 
Yeah lol this is really confusing for me too. It doesn't seem to be very hard but something is obviously not clicking.
 
  • #10
Any new ideas?
 
  • #11
The only reason I think they would give you the 30 degree condition is that you need to account for friction.

try using the 30 degree criteria to get the coefficient of friction.
 
  • #12
You got it rock.freak667!

Kind of a weird question since it didn't say anything about friction. It's not in the friction chapter either. It's a few chapters later. I guess they expect us to use ideas from previous chapters even without making mention of them.

Thanks!
 
  • #13
jamesweston0 said:
It seems to be an easy question but for some reason I can't figure it out.

Homework Statement



2vbsw2x.jpg


If the 10 lb block A slides down the plane with a constant velocity when θ = 30°, determine the acceleration of the block when θ = 45°.

Homework Equations



F = ma

The Attempt at a Solution



I actually am very puzzled by this question. I know that acceleration = 0 at 30° but I don't know how to make use of it. I tried setting the parallel force at 45° to equal ma, then solve for a, but that didn't do it either. Any insight? Thanks.
You would use the 30 degrees to solve for the kinetic friction and then use the value for kinetic friction to solve for the acceleration. I believe its supposed to be a trick question since nowhere is friction mentioned. Cannot be solved without first finding the friction which happens to be 0.5774. Find the Normal force, and with the friction you should come out with the answer. Hope this helps.
 

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