Effective Resistance of Circuit: 4.4 Ohm

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Homework Help Overview

The discussion revolves around determining the effective resistance of a circuit, with specific values mentioned, including 4 ohms and 4.4 ohms. Participants are analyzing the circuit configuration and the role of certain resistors.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to calculate the effective resistance using parallel and series resistance formulas. Questions arise regarding the configuration of resistors, particularly the role of R3 and whether it can be omitted from the circuit. There are requests for diagrams to clarify the circuit layout.

Discussion Status

The discussion is active, with participants providing insights and questioning the assumptions about the circuit's configuration. Some guidance has been offered regarding the implications of a short circuit and the potential to omit certain resistors, but there is no explicit consensus on the final effective resistance value.

Contextual Notes

Participants are working with a circuit diagram that has been referenced but not fully detailed in the posts. There are indications of missing connections and the need for clarification on the circuit layout, which may affect the calculations being discussed.

Icy98
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Homework Statement


What is the effective resistance of this circuit?

Homework Equations


The answer given is 3A. so it means the total effective resistance is 4 ohm. But my answer is 4.4 ohm

The Attempt at a Solution


My attempt:
1/(1/6 + 1/4)+2 = 4.4 ohm
 

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diagram/circuit?
 
andrevdh said:
diagram/circuit?
Thank you. I've just uploaded the picture.
 
Icy98 said:
1/(1/6 + 1/4)+2 = 4.4 ohm

Try to draw the circuit again, but "split up" the connection in point A. What happens with R3 and the connection at its right handside?
 

Attachments

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ImageUploadedByPhysics Forums1447232429.736911.jpg


Is this correct?
 
It is "shorted out" by the wire forming the corner, so there is in effect "no resitance" due to the wire. That means that you can redraw the circuit without the R3 resistor.
 
Icy98 said:
View attachment 91674
Is this correct?

You missed something. There is another cable/connection from point A to the other and of R3.
 
Think of electric current flowing like water from the + terminal towards the - terminal of the battery.
 
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What is the reason that we can omit R3?
 
  • #10
Icy98 said:
What is the reason that we can omit R3?

Complete the drawing from your 3rd post with the missing cable/connection. Then you will see.
 
  • #11
Icy98 said:
What is the reason that we can omit R3?
Good thread ! You really adapted quickly to the PF culture :smile: !

In the upper right of the original picture, there is a ' 0 ##\Omega## resistor ' in parallel with the 2 ##\Omega## resistor. Does that help ?

--
 
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  • #12
ImageUploadedByPhysics Forums1447243370.396140.jpg


Is this correct?
 
  • #13
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  • #14
Thanks a lot to stockzahn, andrevdh and BvU for helping![emoji16][emoji5]️
 
  • #15
It's a pleasure. The potential difference over a small resistor, or in this case the corner wire, is almost zero. That means that the potential difference over the R3 resistor is also almost zero so that almost no current flows through it. It is thus not contributing to the circuit and can be ignored or eliminated.
 

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