(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An electron is projected at an angle of 31.7° above the horizontal at a speed of 8.40×10^5 m/s in a region where the electric field is E = 383j N/C. Neglecting the effects of gravity, calculate the time it takes the electron to return to its initial height.

2. Relevant equations

I first found the electric force that the E field exerts on the electron by using F=qE.

Then I found the acceleration of the electron with a=(q/m)E

Thought perhaps electron would undergo motion similar to a projectile, so then first found the y component of the velocity sin 31.7=opp/8.40x10^5s.

Then applied vf=vi + at solving for t (with vf=0 because it will be when the electron has all potential energy at its highest point)

3. The attempt at a solution

F=383x(-1.6x10^-16C)

=-6.13x10^-14N

a=-6.13x10^-14N/9.11x10^-31kg (mass of electron)

=-6.73x10^16m/s^2

sin 31.7=opp/8.40x10^5m/s

opp= 4.41x10^5m/s

vf=vi +at

0=4.41 + -6.73x10^16m/s^2t

t=6.55x10^-12s (this would be the time to reach max height, so the amount of time to get back down to its initial height would be double this)

so t= 1.31x10^-11s

But this answer is not right... and I'm not show how else to relate t to an electric field. Can anyone point out what i'm doing wrong here??

Thanks SOOO much!! :)

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# Effects of an electric field on a motion of an electron

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